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Q.
Five equal capacitors each with capacitance $C$ are connected as shown in figure. Then, the equivalent capacitance between $A$ and $B$ is
ManipalManipal 2020
Solution:
Consider the given circuit.
The circuit can be redrawn as shown below.
The circuit is a balanced bridge. We can remove the capacitor between $C$ and $D$.
Thus, equivalent capacitance between $A$ and $B$ is
$C_{A B}=\frac{C}{2}+\frac{C}{2}=C$
