Five cells each of e.m.f. E and internal resistance r are connected in series. If due to over sight, one cell is connected wrongly, then the equivalent e.m.f. of the combination is

Question

Five cells each of e.m.f. E and internal resistance r are connected in series. If due to over sight, one cell is connected wrongly, then the equivalent e.m.f. of the combination is (A) 5 E (B) 2 E (C) 3 E (D) 4 E

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/313d6e67f42aca0c4670adb72b168df9-.png" /> Net Emf = E + E + E + E - E = 3E

Q. Five cells each of e.m.f. $E$ and internal resistance $r$ are connected in series. If due to over sight, one cell is connected wrongly, then the equivalent e.m.f. of the combination is

5 E

2 E

3 E

4 E

Net Emf $= E + E + E + E - E$
$= 3 E$

Q. Five cells each of e.m.f. E and internal resistance r are connected in series. If due to over sight, one cell is connected wrongly, then the equivalent e.m.f. of the combination is

5 E

2 E

3 E

4 E

Net Emf =E+E+E+E−E =3E

Q. Five cells each of e.m.f. $E$ and internal resistance $r$ are connected in series. If due to over sight, one cell is connected wrongly, then the equivalent e.m.f. of the combination is

Net Emf $= E + E + E + E - E$
$= 3 E$