First three nearest neighbour distances for body centered cubic lattice are respectively :

Question

First three nearest neighbour distances for body centered cubic lattice are respectively : (A) √2 a , a , √3 a (B) (a/√2), a, √3 a (C) (√3 a/2), a, √2 a (D) (√3 a/2), a, √3 a

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/c0201e0d0cc52d2741b52a2877112eac-.png" /> AC =√2 a (3 rd text nearest ) Ab = a (2 text nd text nearest ) AE =(√3 a /2) (1 text st text nearest )

Q. First three nearest neighbour distances for body centered cubic lattice are respectively :

$2 a, a, 3 a$

$\frac{a}{2}, a, 3 a$

$\frac{3 a}{2}, a, 2 a$

$\frac{3 a}{2}, a, 3 a$

$A C = 2 a (3^{r d} nearest)$

$A b = a (2^{nd} nearest)$

$A E = \frac{3 a}{2} (1^{st} nearest)$

Q. First three nearest neighbour distances for body centered cubic lattice are respectively :

2​a,a,3​a

2​a​,a,3​a

23​a​,a,2​a

23​a​,a,3​a

AC=2​a(3rd nearest ) Ab=a(2nd nearest ) AE=23​a​(1st nearest )

$2 a, a, 3 a$

$\frac{a}{2}, a, 3 a$

$\frac{3 a}{2}, a, 2 a$

$\frac{3 a}{2}, a, 3 a$

$A C = 2 a (3^{r d} nearest)$

$A b = a (2^{nd} nearest)$

$A E = \frac{3 a}{2} (1^{st} nearest)$