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Q. First three nearest neighbour distances for body centered cubic lattice are respectively :

The Solid State

Solution:

image

$AC =\sqrt{2} a \left(3^{ rd } \text { nearest }\right) $

$ Ab = a \left(2^{\text {nd }} \text { nearest }\right) $

$ AE =\frac{\sqrt{3} a }{2} \left(1^{\text {st }} \text { nearest }\right)$