First overtone frequency of a closed pipe of length 'l1' is equal to the 2nd harmonic frequency of an open pipe of length 'l2' .The ratio (l1/l2) =

Question

First overtone frequency of a closed pipe of length 'l1' is equal to the 2nd harmonic frequency of an open pipe of length 'l2' .The ratio (l1/l2) =  (A) (3/4) (B) (4/3) (C) (3/2) (D) (2/3)

Tardigrade Admin · Accepted Answer

(3V/4I1) = (2V/2I2) (l1/l2) = (3/4)

Q. First overtone frequency of a closed pipe of length $^{'} l_{1}^{'}$ is equal to the $2^{n d}$ harmonic frequency of an open pipe of length $^{'} l_{2}^{'}$ .The ratio $\frac{l _{1}}{l _{2}} =$

$\frac{3}{4}$

$\frac{4}{3}$

$\frac{3}{2}$

$\frac{2}{3}$

$\frac{3 V}{4 I _{1}} = \frac{2 V}{2 I _{2}}$
$\frac{l _{1}}{l _{2}} = \frac{3}{4}$

Q. First overtone frequency of a closed pipe of length ′l1′​ is equal to the 2nd harmonic frequency of an open pipe of length ′l2′​ .The ratio l2​l1​​=

43​

34​

23​

32​