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  4. First overtone frequency of a closed pipe of length 'l1' is equal to the 2nd harmonic frequency of an open pipe of length 'l2' .The ratio (l1/l2) =

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Q. First overtone frequency of a closed pipe of length $'l_1'$ is equal to the $2^{nd}$ harmonic frequency of an open pipe of length $'l_2'$ .The ratio $\frac{l_1}{l_2} = $

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Solution:

$\frac{3V}{4I_1} = \frac{2V}{2I_2} $
$\frac{l_1}{l_2} = \frac{3}{4} $