First diffraction minima due to a single slit diffraction is at θ = 30° for a light of wavelength 6000A° .The width of slit.

Question

First diffraction minima due to a single slit diffraction is at θ = 30° for a light of wavelength 6000A° .The width of slit. (A) 1× 10-6 cm (B) 1.2× 10-6 m (C) 2× 10-6 cm (D) 2.4× 10-6 m

Tardigrade Admin · Accepted Answer

sin θ = (x/d) = (λ/b) a sin θ = n λ , a = (n λ/ sin θ)

Q. First diffraction minima due to a single slit diffraction is at $θ$ = 30 $^{\circ}$ for a light of wavelength 6000 $A^{\circ}$ .The width of slit.

$1 \times 1 0^{- 6} c m$

$1.2 \times 1 0^{- 6} m$

$2 \times 1 0^{- 6} c m$

$2.4 \times 1 0^{- 6} m$

sin $θ = \frac{x}{d} = \frac{λ}{b}$ $a$ sin $θ = nλ, a = \frac{nλ}{s i n θ}$

Q. First diffraction minima due to a single slit diffraction is at θ = 30∘ for a light of wavelength 6000A∘ .The width of slit.

1×10−6cm

1.2×10−6m

2×10−6cm

2.4×10−6m