Question

First diffraction minima due to a single slit diffraction is at $\theta$ = 30$^\circ$ for a light of wavelength 6000$A^\circ$ .The width of slit.

• A. $1\times 10^{-6}\,cm$
• B. $1.2\times 10^{-6}\,m$
• C. $2\times 10^{-6}\,cm$
• D. $2.4\times 10^{-6}\,m$

Answer 1

Answer: (B)

sin $ \theta = \frac{x}{d} = \frac{\lambda}{b}$ $a $ sin $ \theta = n \lambda , a = \frac{n \lambda}{\sin \, \theta}$