Tr+1=100Cr(45)100−r(54)r =100Cr(5)4100−r(4)5r Tr+1 will be rational when 4100−r and 5r are integers.
This is possible when 100−r is a multiple of 4 and r is a multiple of 5. ⇒r=0,4,8,…,100 and r=0,5,10,…,100 ⇒r=0,20,40,60,80,100 ⇒ Number of rational terms =6 ⇒ Total number of irrational terms =101−6 =95