Find the total no. of unpaired e-present in the following complexes (I) [Fe(CO)5] (II) [Fe(CN)6]4- (III) [Cr(CO)6] (IV) [Mn(CN)6]4-

Question

Find the total no. of unpaired e-present in the following complexes (I) [Fe(CO)5] (II) [Fe(CN)6]4- (III) [Cr(CO)6] (IV) [Mn(CN)6]4- (A)  (B)  (C)  (D)

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Mn2+: 3d5 4s0 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/cd4151be09b82745d66b98eb97551614-.png" /> Complexes (I, II, III) are diamagnetic hence they have no unpaired electrons.

Q. Find the total no. of unpaired $e^{-}$ present in the following complexes
(I) $[F e (CO)_{5}]$
(II) $[F e (CN)_{6}]^{4 -}$
(III) $[C r (CO)_{6}]$
(IV) $[M n (CN)_{6}]^{4 -}$

$M n^{2 +} : 3 d^{5} 4 s^{0}$

Complexes (I, II, III) are diamagnetic hence they have no unpaired electrons.

Q. Find the total no. of unpaired e−present in the following complexes (I) [Fe(CO)5​] (II) [Fe(CN)6​]4− (III) [Cr(CO)6​] (IV) [Mn(CN)6​]4−

Mn2+:3d54s0 Complexes (I, II, III) are diamagnetic hence they have no unpaired electrons.

Q. Find the total no. of unpaired $e^{-}$ present in the following complexes
(I) $[F e (CO)_{5}]$
(II) $[F e (CN)_{6}]^{4 -}$
(III) $[C r (CO)_{6}]$
(IV) $[M n (CN)_{6}]^{4 -}$

$M n^{2 +} : 3 d^{5} 4 s^{0}$

Complexes (I, II, III) are diamagnetic hence they have no unpaired electrons.