Find the steady-state current through L1 in the figure

Question

Find the steady-state current through L1 in the figure <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-bkb8w7lphs6o.png" /> (A) (V0/R) (B) (V0 L1/R (. L1 + L2 .)) (C) (V0 L2/R (. L1 + L2 .)) (D) none of these

Tardigrade Admin · Accepted Answer

In steady-state, both inductors will be short circuit and current drawn from the cell is, I0=(V0/R) This current will be divided in L1 and L2 like in parallel resistors I1=I0(L2/L1 + L2)

Q. Find the steady-state current through $L_{1}$ in the figure

$\frac{V _{0}}{R}$

$\frac{V _{0} L _{1}}{R ( L _{1} + L _{2} )}$

$\frac{V _{0} L _{2}}{R ( L _{1} + L _{2} )}$

none of these

In steady-state, both inductors will be short circuit and current drawn from the cell is,
$I_{0} = \frac{V _{0}}{R}$
This current will be divided in $L_{1}$ and $L_{2}$ like in parallel resistors
$I_{1} = I_{0} \frac{L _{2}}{L _{1} + L _{2}}$

Q. Find the steady-state current through L1​ in the figure

RV0​​

R(L1​+L2​)V0​L1​​

R(L1​+L2​)V0​L2​​