Question

Find the resultant amplitude of the following simple harmonic equations:

$x_1=5sin\omega t$

$x_2=5sin\left(\omega t+53^{\circ }\right)$

$x_3=-10cos\omega t$

• A. $5$
• B. $10$
• C. $15$
• D. $20$

Answer 1

Answer: (B)

$x_1=5sin\omega t$
$x_2=5sin\left(\omega t+53^{\circ }\right)$
$x_3=-10cos\omega t$
we can write $x_3=10sin\left(\omega t-90^{\circ }\right)$ Finding the resultant amplitude by vector notation.

Resultant Amplitude $|R|=\sqrt{8^2+6^2}=10$ .