Find the ratio of the time period of revolution of electron in He +ion sample in the orbit where the path length is 3 times the de Broglie wavelength to the time period of revolution in the ground state.

Question

Find the ratio of the time period of revolution of electron in He +ion sample in the orbit where the path length is 3 times the de Broglie wavelength to the time period of revolution in the ground state. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

2 π r=3 λ ⇒ (2 π r/λ)=3 ⇒ n=3 ∴ (T1/T2)=(n13/n23) =(33/13)=27

Q. Find the ratio of the time period of revolution of electron in $H e^{+}$ ion sample in the orbit where the path length is $3$ times the de Broglie wavelength to the time period of revolution in the ground state.

$2 π r = 3 λ$
$\Rightarrow \frac{2 π r}{λ} = 3$
$\Rightarrow n = 3$
$∴ \frac{T _{1}}{T _{2}} = \frac{n _{1}^{3}}{n _{2}^{3}}$
$= \frac{3 ^{3}}{1 ^{3}} = 27$

Q. Find the ratio of the time period of revolution of electron in He+ion sample in the orbit where the path length is 3 times the de Broglie wavelength to the time period of revolution in the ground state.

2πr=3λ ⇒λ2πr​=3 ⇒n=3 ∴T2​T1​​=n23​n13​​ =1333​=27

Q. Find the ratio of the time period of revolution of electron in $H e^{+}$ ion sample in the orbit where the path length is $3$ times the de Broglie wavelength to the time period of revolution in the ground state.

$2 π r = 3 λ$
$\Rightarrow \frac{2 π r}{λ} = 3$
$\Rightarrow n = 3$
$∴ \frac{T _{1}}{T _{2}} = \frac{n _{1}^{3}}{n _{2}^{3}}$
$= \frac{3 ^{3}}{1 ^{3}} = 27$