Find the product of the common prime factors of HCF of 72 and 96 .

Question

Find the product of the common prime factors of HCF of 72 and 96 . (A) 2 (B) 3 (C) 6 (D) 5

Tardigrade Admin · Accepted Answer

Factors of 72=22 × 33 Factors of 96=25 × 31 operatornameHCF(72,96)=23 × 31. Therefore, The common prime factors are 2 and 3. The product of the prime factors of the HCF =2 × 3=6.

Q. Find the product of the common prime factors of HCF of 72 and 96 .

2

3

6

5

Factors of $72 = 2^{2} \times 3^{3}$
Factors of $96 = 2^{5} \times 3^{1}$
$HCF (72, 96) = 2^{3} \times 3^{1}$ .
Therefore, The common prime factors are 2 and 3.
The product of the prime factors of the HCF $= 2 \times 3 = 6$ .

Q. Find the product of the common prime factors of HCF of 72 and 96 .

2

3

6

5

Factors of 72=22×33 Factors of 96=25×31 HCF(72,96)=23×31. Therefore, The common prime factors are 2 and 3. The product of the prime factors of the HCF =2×3=6.

Factors of $72 = 2^{2} \times 3^{3}$
Factors of $96 = 2^{5} \times 3^{1}$
$HCF (72, 96) = 2^{3} \times 3^{1}$ .
Therefore, The common prime factors are 2 and 3.
The product of the prime factors of the HCF $= 2 \times 3 = 6$ .