Find the potential at the centre of a square of side √2m . Which carries at its four comers charges q1=3× 10-6C,q2=-3× 10-6C, q3=-4× 10-6C,q4=7× 10-6C

Question

Find the potential at the centre of a square of side √2m . Which carries at its four comers charges q1=3× 10-6C,q2=-3× 10-6C, q3=-4× 10-6C,q4=7× 10-6C  (A)  2.7× 104V  (B)  1.5× 103V  (C)  3× 102V  (D)  5× 103V

Tardigrade Admin · Accepted Answer

The potential V=(1/4π ε 0)(1/r)(q1+q2+q3+q4) V=(9× 109)( (1/1m) ) (3-3-4+7)× 10-6C =2.7× 104(N-m/C)=2.7× 104(J/C) =2.7× 104V

Q. Find the potential at the centre of a square of side $2 m$ . Which carries at its four comers charges $q_{1} = 3 \times 10^{- 6} C, q_{2} = - 3 \times 10^{- 6} C,$ $q_{3} = - 4 \times 10^{- 6} C, q_{4} = 7 \times 10^{- 6} C$

$2.7 \times 10^{4} V$

$1.5 \times 10^{3} V$

$3 \times 10^{2} V$

$5 \times 10^{3} V$

$3 \times 10^{3} V$

The potential $V = \frac{1}{4 π ε _{0}} \frac{1}{r} (q_{1} + q_{2} + q_{3} + q_{4})$
$V = (9 \times 10^{9}) (\frac{1}{1 m}) {(3 - 3 - 4 + 7) \times 10^{- 6} C}$
$= 2.7 \times 10^{4} \frac{N - m}{C} = 2.7 \times 10^{4} \frac{J}{C}$
$= 2.7 \times 10^{4} V$

Q. Find the potential at the centre of a square of side 2​m . Which carries at its four comers charges q1​=3×10−6C,q2​=−3×10−6C, q3​=−4×10−6C,q4​=7×10−6C

2.7×104V

1.5×103V

3×102V

5×103V

3×103V

The potential V=4πε0​1​r1​(q1​+q2​+q3​+q4​) V=(9×109)(1m1​){(3−3−4+7)×10−6C} =2.7×104CN−m​=2.7×104CJ​ =2.7×104V