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Question
Mathematics
Find the order and degree of the differential equation [1+ ((dy/dx))2 + sin ((dy/dx))](3/4) = (d2y/dx2)
Q. Find the order and degree of the differential equation
[
1
+
(
d
x
d
y
)
2
+
sin
(
d
x
d
y
)
]
4
3
=
d
x
2
d
2
y
2491
229
KCET
KCET 2016
Differential Equations
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A
order=2
degree=3
9%
B
order=2
degree=4
14%
C
order=2
degree=
4
3
17%
D
order=2
degree= not defined
60%
Solution:
We have,
[
1
+
(
d
x
d
y
)
2
+
sin
(
d
x
d
y
)
]
3/4
=
d
x
2
d
2
y
⇒
(
d
x
2
d
2
y
)
4
=
[
1
+
(
d
x
d
y
)
2
+
sin
(
d
x
d
y
)
]
8
Clearly, order
=
2
and degree
=
not defined