Find the number of ways of choosing two red cards and two black cards from a pack of 52 playing cards.

Question

Find the number of ways of choosing two red cards and two black cards from a pack of 52 playing cards. (A) 105620 (B)  105624  (C)  105625  (D)  105600

Tardigrade Admin · Accepted Answer

There are 26 red cards and 26 black cards. Therefore, the required number of ways = 26C2 × 26C2 = ((26!/2! 24!))2 = (325)2 = 105625

Q. Find the number of ways of choosing two red cards and two black cards from a pack of $52$ playing cards.

$105620$

$105624$

$105625$

$105600$

There are $26$ red cards and $26$ black cards. Therefore, the required number of ways
$=^{26} C_{2} \times^{26} C_{2}$
$= (\frac{26 !}{2 ! 24 !})^{2} = (325)^{2}$
$= 105625$

Q. Find the number of ways of choosing two red cards and two black cards from a pack of 52 playing cards.

105620

105624

105625

105600