Find the maximum/minimum value of the quadratic expression 3 x2+10 x+8.

Question

Find the maximum/minimum value of the quadratic expression 3 x2+10 x+8. (A) Minimum value is 3 (B) Maximum value is 3 (C) Minimum value is 13 (D) Maximum value is 13

Tardigrade Admin · Accepted Answer

Given: x2+6 x+12 which is in the form of a x2+b x+c. where a=1 >0 text where a=1 >0 text Minimum value =(4 a c-b2/4 a) =(4(3)(12)-36/4(3)) =(48-36/4)=3

Q. Find the maximum/minimum value of the quadratic expression $3 x^{2} + 10 x + 8$ .

Minimum value is 3

Maximum value is 3

Minimum value is 13

Maximum value is 13

Given: $x^{2} + 6 x + 12$
which is in the form of $a x^{2} + b x + c$ .
where $a = 1 > 0$
$where a = 1 > 0$
$Minimum value = \frac{4 a c - b ^{2}}{4 a}$
$= \frac{4 ( 3 ) ( 12 ) - 36}{4 ( 3 )}$
$= \frac{48 - 36}{4} = 3$

Q. Find the maximum/minimum value of the quadratic expression 3x2+10x+8.