Find the locus of a point which moves so that sum of the squares of its distance from the axes is equal to 3 .

Question

Find the locus of a point which moves so that sum of the squares of its distance from the axes is equal to 3 . (A) x2+y2=9 (B) x2+y2+=3 (C) |x|+|y|=3 (D) x2-y2=3

Tardigrade Admin · Accepted Answer

Let point (h, k) Distance from y-axis =| h | -------------------x -----------=(k) ∴ h2+k2 ≡ 3 x2+y2-3

Q. Find the locus of a point which moves so that sum of the squares of its distance from the axes is equal to 3 .

$x^{2} + y^{2} = 9$

$x^{2} + y^{2} + = 3$

$∣ x ∣ + ∣ y ∣ = 3$

$x^{2} - y^{2} = 3$

Let point $(h, k)$
Distance from $y$ -axis $= ∣ h ∣$
------------------- $x$ ----------- $= (k)$
$∴ h^{2} + k^{2} \equiv 3$
$x^{2} + y^{2} - 3$

Q. Find the locus of a point which moves so that sum of the squares of its distance from the axes is equal to 3 .

x2+y2=9

x2+y2+=3

∣x∣+∣y∣=3

x2−y2=3

Let point (h,k) Distance from y-axis =∣h∣ -------------------x -----------=(k) ∴h2+k2≡3 x2+y2−3

$x^{2} + y^{2} = 9$

$x^{2} + y^{2} + = 3$

$∣ x ∣ + ∣ y ∣ = 3$

$x^{2} - y^{2} = 3$

Let point $(h, k)$
Distance from $y$ -axis $= ∣ h ∣$
------------------- $x$ ----------- $= (k)$
$∴ h^{2} + k^{2} \equiv 3$
$x^{2} + y^{2} - 3$