Q.
Find the largest integral value of m for which the quadratic expression y=x2+(2m+4)x+7m+8 is positive for all x∈R
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Complex Numbers and Quadratic Equations
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Answer: 3
Solution:
Given expression >0 for all x. ⇔Δ<0 as leading coefficient >0 ⇔4(m+2)2−4(7m+8)<0 ⇔m2+4m+4−7m−8<0 ⇔m2−3m−4<0 ⇔(m−4)(m+1)<0 ⇔−1<m<4 ⇒ Largest integral value of m=3