Find the hydrolysis product when a phosphodiester bond of nucleotide breaks.

Question

Find the hydrolysis product when a phosphodiester bond of nucleotide breaks. (A) 3-OH-deoxyribose-5-PO3-4 (B) 5-OH-deoxyribose-3-PO3-4 (C) 2-OH-deoxyribose-2-PO3-4 (D) 4-OH-deoxyribose-2-PO3-4

Tardigrade Admin · Accepted Answer

A phosphodiester bond occurs when exactly two of the hydroxyl groups in phosphoric acid react with hydroxyl groups on other molecules to form two ester bonds.

Q. Find the hydrolysis product when a phosphodiester bond of nucleotide breaks.

3-OH-deoxyribose-5- $P O_{4}^{3 -}$

5-OH-deoxyribose-3- $P O_{4}^{3 -}$

2-OH-deoxyribose-2- $P O_{4}^{3 -}$

4-OH-deoxyribose-2- $P O_{4}^{3 -}$

A phosphodiester bond occurs when exactly two of the hydroxyl groups in phosphoric acid react with hydroxyl groups on other molecules to form two ester bonds.

Q. Find the hydrolysis product when a phosphodiester bond of nucleotide breaks.

3-OH-deoxyribose-5-PO43−​

5-OH-deoxyribose-3-PO43−​

2-OH-deoxyribose-2-PO43−​

4-OH-deoxyribose-2-PO43−​

A phosphodiester bond occurs when exactly two of the hydroxyl groups in phosphoric acid react with hydroxyl groups on other molecules to form two ester bonds.

3-OH-deoxyribose-5- $P O_{4}^{3 -}$

5-OH-deoxyribose-3- $P O_{4}^{3 -}$

2-OH-deoxyribose-2- $P O_{4}^{3 -}$

4-OH-deoxyribose-2- $P O_{4}^{3 -}$