Question

Find the final product 'E'

$\begin{array}{l}{\mathrm{CH}}_2\mathrm{OH}-\mathrm{CH}={\mathrm{CH}}_2\underset{\text{ (ii) }}{\stackrel{\text{ (i) })}{{\mathrm{NaSO}}_4}\mathrm{H}}(\mathrm{A})\stackrel{{\mathrm{KHSO}}_4}{\to }(\mathrm{B})\stackrel{\mathrm{Zn}-\mathrm{Hg}/\text{ conc. }\mathrm{HCl}}{\to }\\ \text{ (C) }\underset{{\mathrm{CCl}}_4}{\stackrel{\mathrm{NBS}/\mathrm{hv}}{\to }}(\mathrm{D})\stackrel{{\left({\mathrm{CH}}_3\right)}_2\mathrm{CuLi}}{\to }(\mathrm{E})\end{array}$

• A. But-2-ene
• B. But-1-ene
• C. Isopentene
• D. Pen-2-ene

Answer 1

Answer: (B)

Here the final product E is Butene and the reaction sequence is as follows