Question

Find the equation of chord of the circle $x^2+y^2=8x$ bisected at the point $(4,3)$

• A. y = 3
• B. y = 1
• C. y = 6
• D. y = 7

Answer 1

Answer: (A)

$T=S_1$
$\Rightarrow x(4)+y(3)-4(x+4)$
$=16+9-32$
$\Rightarrow 3y-9$
$=0\Rightarrow y=3$