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Q. Find the equation of chord of the circle $x^2 + y^2 = 8x$ bisected at the point $(4, 3)$

BITSATBITSAT 2010

Solution:

$T=S_{1}$
$\Rightarrow x(4)+y(3)-4(x+4)$
$=16+9-32$
$\Rightarrow 3 y-9$
$=0 \Rightarrow y=3$