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Question
Physics
Find the dimensions of electric permittivity.
Q. Find the dimensions of electric permittivity.
1525
193
UPSEE
UPSEE 2005
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A
[
A
2
M
−
1
L
−
3
T
4
]
B
[
A
2
M
−
1
L
−
3
T
0
]
C
[
A
M
−
1
L
−
3
T
4
]
D
[
A
2
M
0
L
−
3
T
4
]
Solution:
From Coulomb’s law, the force of attraction/repulsion between two point charges
q
,
q
separated by distance
r
is
F
=
4
π
ε
0
1
r
2
q
2
⇒
ε
0
=
4
π
1
⋅
F
r
2
q
2
where
ε
0
is electric permittivity.
Dimensions of
ε
0
=
[
M
L
T
−
2
]
[
L
2
]
[
A
T
]
2
ε
0
=
[
A
2
M
−
1
L
−
3
T
4
]