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Question
Mathematics
Find the coefficient of x6y3 in the expansion of (x + 2y)9.
Q. Find the coefficient of
x
6
y
3
in the expansion of
(
x
+
2
y
)
9
.
2238
223
Binomial Theorem
Report Error
A
674
16%
B
670
21%
C
676
26%
D
672
37%
Solution:
Let
x
6
y
3
be the
(
r
+
1
)
t
h
term in the expansion of
(
x
+
2
y
)
9
.
Now
T
r
+
1
=
9
C
r
x
9
−
r
(
2
y
)
r
=
9
C
r
2
r
⋅
x
9
−
r
⋅
y
r
.
Comparing the indices of
x
and
y
in
x
6
y
3
and in
T
r
+
1
, we get
r
=
3
.
Thus, the coefficient of
x
6
y
3
=
9
C
3
2
3
=
672
.