Question

Find the binary equivalent of the decimal number $(111{)}_{10}$

• A. $(1011111{)}_2$
• B. $(1110001{)}_2$
• C. $(1101111{)}_2$
• D. $(1011001{)}_2$

Answer 1

Answer: (C)

$(111{)}_{10}=(2^6)1+(2^5)1+(2^4)0+(2^3)1+(2^2)1+(2^1)1$
$+(2^6)1=(1101111{)}_2$