Question

Find current in the branch $CD$ (in $A$) of the circuit shown in figure.

Answer 1

Answer: 15

Circuit can be redrawn as shown in figure below

The equivalent resistance across the battery, $R_{eq}=\frac{3}{2}\Omega$
$\Rightarrow I=\frac{V}{R_{eq}}=20A$
Current in $I_{CD}=I_{AC}+I_B$
$\Rightarrow I_{CD}=15A$