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Q.
Find current in the branch $C D$ (in $A$) of the circuit shown in figure.
Current Electricity
Solution:
Circuit can be redrawn as shown in figure below
The equivalent resistance across the battery, $R_{ eq }=\frac{3}{2} \Omega$
$\Rightarrow I=\frac{V}{R_{ eq }}=20\, A$
Current in $I_{C D}=I_{A C}+I_{B}$
$\Rightarrow I_{C D}=15\, A$
