Figure shows three spherical and equipotential surfaces A, B and C round a point charge q. The potential difference VA-VB=VB-VC. If t1 and t2 be the distance between them. Then:

Question

Figure shows three spherical and equipotential surfaces A, B and C round a point charge q. The potential difference VA-VB=VB-VC. If t1 and t2 be the distance between them. Then: (A)  t1=t2  (B)  t1>t2  (C)  t1<t2  (D)  t1 le t2

Tardigrade Admin · Accepted Answer

Potential difference between two equipotential surfaces A and B, VA-VB=kq( (1/rA)-(1/rB) ) =kq( (rB-rA/rArB) ) =(kqt1/rArB) or t1=((VA-VB)rArB/kq) or t1 propto rArB Similarly, t2 propto rBrC Since rA<rB<rC, therefore rArB<rBrC ∴ t1<t2

Q. Figure shows three spherical and equipotential surfaces A, B and C round a point charge q. The potential difference $V_{A} - V_{B} = V_{B} - V_{C} .$ If $t_{1}$ and $t_{2}$ be the distance between them. Then:

$t_{1} = t_{2}$

$t_{1} > t_{2}$

$t_{1} < t_{2}$

$t_{1} \leq t_{2}$

Q. Figure shows three spherical and equipotential surfaces A, B and C round a point charge q. The potential difference VA​−VB​=VB​−VC​. If t1​ and t2​ be the distance between them. Then:

t1​=t2​

t1​>t2​

t1​<t2​

t1​≤t2​

Q. Figure shows three spherical and equipotential surfaces A, B and C round a point charge q. The potential difference $V_{A} - V_{B} = V_{B} - V_{C} .$ If $t_{1}$ and $t_{2}$ be the distance between them. Then:

$t_{1} = t_{2}$

$t_{1} > t_{2}$

$t_{1} < t_{2}$

$t_{1} \leq t_{2}$