Figure shows three spherical and equipotential surfaces A, B and C round a point charge q. The potential difference VA - VB = VB - VC. If t1 and t2 be the distances between them, then

Question

Figure shows three spherical and equipotential surfaces A, B and C round a point charge q. The potential difference VA - VB = VB - VC. If t1 and t2 be the distances between them, then (A)  t1 = t1 (B)  t1 > t2 (C)  t1 < t2 (D)  t1 le t2

Tardigrade Admin · Accepted Answer

PotentiaI difference between two equipotential surfaces A and B.

V_{A} - V_{B} = k q (\frac{1}{r _{A}} - \frac{1}{r _{B}}) = k q (\frac{r _{B} - r _{A}}{r _{A} r _{B}}) = \frac{k q t _{1}}{r _{A} r _{B}}

or

t_{1} = \frac{( V _{A} - V _{B} ) r _{A} r _{B}}{k q}

or

t_{1} \propto r_{A} r_{B}

Simiiarly,

t_{1} \propto r_{B} r_{C}

Since,

r_{A} < r_{B} < r_{C}, t h ere f ore r_{A} r_{B} < r_{B} r_{C}

∴ t_{1} < t_{2}

Q. Figure shows three spherical and equipotential surfaces A, B and C round a point charge q. The potential difference $V_{A} - V_{B} = V_{B} - V_{C} . I f t_{1} an d t_{2}$ be the distances between them, then

$t_{1} = t_{1}$

$t_{1} > t_{2}$

$t_{1} < t_{2}$

$t_{1} \leq t_{2}$

Q. Figure shows three spherical and equipotential surfaces A, B and C round a point charge q. The potential difference VA​−VB​=VB​−VC​.Ift1​andt2​ be the distances between them, then

t1​=t1​

t1​>t2​

t1​<t2​

t1​≤t2​

Q. Figure shows three spherical and equipotential surfaces A, B and C round a point charge q. The potential difference $V_{A} - V_{B} = V_{B} - V_{C} . I f t_{1} an d t_{2}$ be the distances between them, then

$t_{1} = t_{1}$

$t_{1} > t_{2}$

$t_{1} < t_{2}$

$t_{1} \leq t_{2}$