Figure shows three circular arcs, each of radius R and total charge as indicated. The net electric potential at the center of curvature is

Question

Figure shows three circular arcs, each of radius R and total charge as indicated. The net electric potential at the center of curvature is (A) (Q/2 π ε0 R) (B) (5 Q/12 π ε0 R) (C) (3 Q/32 π ε0 R) (D) none of these

Tardigrade Admin · Accepted Answer

Charge can be considered as located at a distance R from the center. Total charge is (Q-2 Q+3 Q)=2 Q Hence V=(1/4 π ε0) (2 Q/R)=(Q/2 π ε0 R)

Q. Figure shows three circular arcs, each of radius $R$ and total charge as indicated. The net electric potential at the center of curvature is

$\frac{Q}{2 π ε _{0} R}$

$\frac{5 Q}{12 π ε _{0} R}$

$\frac{3 Q}{32 π ε _{0} R}$

none of these

Charge can be considered as located at a distance $R$ from the center. Total charge is $(Q - 2 Q + 3 Q) = 2 Q$
Hence $V = \frac{1}{4 π ε _{0}} \frac{2 Q}{R} = \frac{Q}{2 π ε _{0} R}$

Q. Figure shows three circular arcs, each of radius R and total charge as indicated. The net electric potential at the center of curvature is

2πε0​RQ​

12πε0​R5Q​

32πε0​R3Q​