Figure shows three charged circular arcs, each of radius R, their centres are at same point and total charge as indicated. The net electric potential at the centre of curvature :-

Question

Figure shows three charged circular arcs, each of radius R, their centres are at same point and total charge as indicated. The net electric potential at the centre of curvature :- <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-hkywwfahslrcnvxc.jpg" /> (A) (Q/2 π ϵ 0 R) (B) (5 Q/12 π ϵ 0 R) (C) (3 Q/32 π ϵ 0 R) (D) none of these

Tardigrade Admin · Accepted Answer

Charge can be considered as located at a distance R from the centre. Total charge is (Q - 2 Q + 3 Q) Hence V=(1/4 π ϵ 0)(2 Q/R)=(Q/2 π ϵ 0 R)

Q. Figure shows three charged circular arcs, each of radius $R,$ their centres are at same point and total charge as indicated. The net electric potential at the centre of curvature :-

$\frac{Q}{2 π ϵ _{0} R}$

$\frac{5 Q}{12 π ϵ _{0} R}$

$\frac{3 Q}{32 π ϵ _{0} R}$

none of these

Charge can be considered as located at a distance
$R$ from the centre. Total charge is $(Q - 2 Q + 3 Q)$
Hence $V = \frac{1}{4 π ϵ _{0}} \frac{2 Q}{R} = \frac{Q}{2 π ϵ _{0} R}$

Q. Figure shows three charged circular arcs, each of radius R, their centres are at same point and total charge as indicated. The net electric potential at the centre of curvature :-

2πϵ0​RQ​

12πϵ0​R5Q​

32πϵ0​R3Q​