Figure shows the position-time graph of a particle of mass 4 kg. Let the force on the particle for t

Question

Figure shows the position-time graph of a particle of mass 4 kg. Let the force on the particle for t < 0, 0 < t < 4 s , t > 4 s be F1, F2 and F3 respectively. Then

(A) F1 = F2=F3=0 (B) F1 > F2 = F3 (C) F1> F2> F3 (D) F1 < F2< F3

Tardigrade Admin · Accepted Answer

For t < 0 and t > 4 s, the position of the particle is not changing i.e., the particle is at rest. So no force is acting on the particle at these intervals For 0 < t < 4 s, the position of the particle is continuously changing. As the position-time graph is a straight line, the motion of the particle is uniform, so acceleration, a=0 Hence no force acts on the particle during this interval also

Q. Figure shows the position-time graph of a particle of mass $4 k g$ . Let the force on the particle for $t < 0, 0 < t < 4 s, t > 4 s$ be $F_{1}, F_{2}$ and $F_{3}$ respectively. Then

$F_{1} = F_{2} = F_{3} = 0$

$F_{1} > F_{2} = F_{3}$

$F_{1} > F_{2} > F_{3}$

$F_{1} < F_{2} < F_{3}$

Q. Figure shows the position-time graph of a particle of mass 4kg. Let the force on the particle for t<0,0<t<4s,t>4s be F1​,F2​ and F3​ respectively. Then

F1​=F2​=F3​=0

F1​>F2​=F3​

F1​>F2​>F3​

F1​<F2​<F3​

Q. Figure shows the position-time graph of a particle of mass $4 k g$ . Let the force on the particle for $t < 0, 0 < t < 4 s, t > 4 s$ be $F_{1}, F_{2}$ and $F_{3}$ respectively. Then

$F_{1} = F_{2} = F_{3} = 0$

$F_{1} > F_{2} = F_{3}$

$F_{1} > F_{2} > F_{3}$

$F_{1} < F_{2} < F_{3}$