Question

Figure shows the position-time graph of a particle of mass $4\, kg$. Let the force on the particle for $t < \,0, 0 < \,t <\, 4 s , t >\, 4\, s$ be $F_{1}, F_{2}$ and $F_{3}$ respectively. Then

• A. $ F_{1} = F_{2}=F_{3}=0$
• B. $F_{1} >\,F_{2} = F_{3}$
• C. $F_{1}>\,F_{2}>\,F_{3}$
• D. $F_{1} <\,F_{2}<\,F_{3}$

Answer 1

Answer: (A)

For $t <\,0$ and $t >\,4 \,s$, the position of the particle is not changing i.e., the particle is at rest. So no force is acting on the particle at these intervals
For $0 <\, t <\,4\,s$, the position of the particle is continuously changing. As the position-time graph is a straight line, the motion of the particle is uniform, so acceleration, $a=0$ Hence no force acts on the particle during this interval also