Figure shows the kinetic energy K of a simple pendulum versus its angle θ from the vertical. The pendulum bob has mass 0.2 kg . The length of the pendulum is equal to (g=10 m / s 2):

Question

Figure shows the kinetic energy K of a simple pendulum versus its angle θ from the vertical. The pendulum bob has mass 0.2 kg . The length of the pendulum is equal to (g=10 m / s 2): <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/3916e9a14005a7be71a3d9b897e2bc64-.png" /> (A) 2.0 m (B) 1.8 m (C) 1.5 m (D) 1.2 m

Tardigrade Admin · Accepted Answer

Given that from graph (1/2) m Vm2 =15 × 10-3 Vm =√0.150 m / s A ω =√0.150 m / s L θm ⋅ √(g/L) =√0.150 m / s ⇒ √g L =(√0.150/100 × 10-3) ⇒ L =(0.150/0.1)=1.5 m

Q. Figure shows the kinetic energy $K$ of a simple pendulum versus its angle $θ$ from the vertical. The pendulum bob has mass $0.2 k g .$ The length of the pendulum is equal to $(g = 10 m / s^{2})$ :

2.0 m

1.8 m

1.5 m

1.2 m

Given that from graph
$\frac{1}{2} m V_{m}^{2} = 15 \times 1 0^{- 3}$
$V_{m} = 0.150 m / s$
$A ω = 0.150 m / s$
$L θ_{m} \cdot \frac{g}{L} = 0.150 m / s$
$\Rightarrow gL = \frac{0.150}{100 \times 1 0 ^{- 3}}$
$\Rightarrow L = \frac{0.150}{0.1} = 1.5 m$

Q. Figure shows the kinetic energy K of a simple pendulum versus its angle θ from the vertical. The pendulum bob has mass 0.2kg. The length of the pendulum is equal to (g=10m/s2) :