Question

Figure shows charge $(q)$ versus voltage $(V)$ graph for series and parallel combination of two given capacitors. The capacitances are :

• A. $50\mu F$ and $30\mu F$
• B. $20\mu F$ and $30\mu F$
• C. $60\mu F$ and $40\mu F$
• D. $40\mu F$ and $10\mu F$

Answer 1

Answer: (D)

As $q=CV$
Hence slope of graph will give capacitance.
Slope will be more in parallel combination.
Hence capacitance in parallel should be $50\mu F$ & in series combination must be $8\mu F$.
Only in option $40\mu F$ & $10\mu F$
$C_{\text{parallel}}=40+10=50\mu F$
$C_{\text{series}}=\frac{40\times 10}{40+10}=8\mu F$