Figure shows a thin metallic triangular sheet A B C . The mass of the sheet is M. The moment of inertia of the sheet about side A C is:

Question

Figure shows a thin metallic triangular sheet A B C . The mass of the sheet is M. The moment of inertia of the sheet about side A C is: (A) (M l2/18) (B) (M l2/12) (C) (M l2/6) (D) (M l2/4)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/7480d40551bf37d3a1c8e256444b8956-.png" /> h=(l/√2) IA C=(1/6) M h2=(M l2/12)

Q. Figure shows a thin metallic triangular sheet $A BC .$ The mass of the sheet is $M$ . The moment of inertia of the sheet about side $A C$ is:

$\frac{M l ^{2}}{18}$

$\frac{M l ^{2}}{12}$

$\frac{M l ^{2}}{6}$

$\frac{M l ^{2}}{4}$

$h = \frac{l}{2}$
$I_{A C} = \frac{1}{6} M h^{2} = \frac{M l ^{2}}{12}$

Q. Figure shows a thin metallic triangular sheet ABC. The mass of the sheet is M. The moment of inertia of the sheet about side AC is:

18Ml2​

12Ml2​

6Ml2​

4Ml2​