Figure shows a series LCR circuit connected to a variable frequency 230 V source. The source frequency which drives the circuit in resonance is

Question

Figure shows a series LCR circuit connected to a variable frequency 230 V source. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/f0e55cada411c1e2e4865574a5fa3ccb-.jpeg" /> The source frequency which drives the circuit in resonance is (A) 4 Hz (B) 5 Hz (C) 6 Hz (D) 8 Hz

Tardigrade Admin · Accepted Answer

Here, L = 5 H, C= 80 μ F = 80 × 10-6 F, R = 40 Ω Vrms=230 V The resonant angular frequency is ωr=(1/√LC) =(1/√5×80×10-6) =50 rad s-1 ∴ upsilonr=(ω/2π) =(50/2π) 8 Hz

Q. Figure shows a series $L CR$ circuit connected to a variable frequency $230 V$ source.

The source frequency which drives the circuit in resonance is

$4 Hz$

$5 Hz$

$6 Hz$

$8 Hz$

Here, $L = 5 H$ ,
$C = 80 μ F = 80 \times 1 0^{- 6} F$ ,
$R = 40 Ω$
$V_{r m s} = 230 V$
The resonant angular frequency is
$ω_{r} = \frac{1}{L C}$
$= \frac{1}{5 \times 80 \times 1 0 ^{- 6}}$
$= 50 r a d s^{- 1}$
$∴ υ_{r} = \frac{ω}{2 π}$
$= \frac{50}{2 π}$
$8 Hz$

Q. Figure shows a series LCR circuit connected to a variable frequency 230V source. The source frequency which drives the circuit in resonance is

4Hz

5Hz

6Hz

8Hz