Figure shows a man of mass 55 kg standing stationary with respect to a horizontal conveyor belt that is accelerating with 1 m s-2. The net force acting on the man is

Question

Figure shows a man of mass 55 kg standing stationary with respect to a horizontal conveyor belt that is accelerating with 1 m s-2. The net force acting on the man is (A) 35 N (B) 45 N (C) 55 N (D) 65 N

Tardigrade Admin · Accepted Answer

Here, mass of the man, M=55 kg As the man is standing stationary w.r.t. the belt, acceleration of man = acceleration of belt. ∴ Acceleration of man, a=1 m s-2 ∴ Net force on the man F=Ma =(55 kg) (1 m s-2) =55 N

Q. Figure shows a man of mass $55 k g$ standing stationary with respect to a horizontal conveyor belt that is accelerating with $1 m$ $s^{- 2}$ . The net force acting on the man is

$35 N$

$45 N$

$55 N$

$65 N$

Here, mass of the man, $M = 55 k g$
As the man is standing stationary w.r.t. the belt, acceleration of man = acceleration of belt.
$∴$ Acceleration of man, $a = 1 m$ $s^{- 2}$
$∴$ Net force on the man
$F = M a$ $= (55 k g)$ $(1 m s^{- 2})$ $= 55 N$

Q. Figure shows a man of mass 55kg standing stationary with respect to a horizontal conveyor belt that is accelerating with 1m s−2. The net force acting on the man is

35N

45N

55N

65N