Figure here shows the frictional force versus displacement for a particle in motion. The loss of kinetic energy in travelling over S = 0 to 20 m will be

Question

Figure here shows the frictional force versus displacement for a particle in motion. The loss of kinetic energy in travelling over S = 0 to 20 m will be (A) 250 J (B) 200 J (C) 150 J (D) 10 J

Tardigrade Admin · Accepted Answer

Work done by friction = Area under the F vs 5 graph Each square is 25 J, effectively there are 10 squares in the area. Hence loss in K.E.= Workdone by friction = 250 J.

Q. Figure here shows the frictional force versus displacement for a particle in motion. The loss of kinetic energy in travelling over $S = 0$ to $20 m$ will be

250 J

200 J

150 J

10 J

Work done by friction = Area under the F vs 5 graph Each square is $25 J$ , effectively there are 10 squares in the area. Hence loss in K.E.= Workdone by friction $= 250 J$ .

Q. Figure here shows the frictional force versus displacement for a particle in motion. The loss of kinetic energy in travelling over S=0 to 20m will be