Question

$FeC{r}_2{O}_4$ (chromite) is a good source of chromium and its compounds like $N{a}_{2}Cr{O}_4,N{a}_{2}C{r}_2{O}_7$ Questions are based on the following reactions
$P:FeC{r}_2{O}_4+NaOH+$ air $\to A+F{e}_2{O}_3$
$Q:A+B\to N{a}_{2}C{r}_2{O}_7$
R: $N{a}_{2}C{r}_2{O}_7+X\stackrel{\Delta }{\to }C{r}_2{O}_3$
$S:C{r}_2{O}_3+Y\to Cr$
Compound $(A)$ and $(B)$ are

• A. $N{a}_{2}Cr{O}_4,H_{2}S{O}_4$
• B. $N{a}_{2}C{r}_2{O}_7,HCl$
• C. $N{a}_{2}Cr{O}_5,H_{2}S{O}_4$
• D. $N{a}_4\left[Fe(OH{)}_6\right],H_{2}S{O}_4$

Answer 1

Answer: (A)

Correct answer is (a) $N{a}_{2}Cr{O}_4,H_{2}S{O}_4$