[ Fe ( H 2 O )5 NO ]2+ is brown-ring complex in NO 3-. In this complex

Question

[ Fe ( H 2 O )5 NO ]2+ is brown-ring complex in NO 3-. In this complex (A) NO transfers its electron to Fe 2+ so that there are three electrons unpaired making iron as Fe ( I ) and nitrosyl as NO + (B) Magnetic moment of Fe is 3.87 BM (C) The colour is due to charge transfer (D) All of the above are correct statements

Tardigrade Admin · Accepted Answer

Correct answer is (c) The colour is due to charge transfer

Q. $[F e (H_{2} O)_{5} NO]^{2 +}$ is brown-ring complex in $N O_{3}^{-}$ . In this complex

$NO$ transfers its electron to $F e^{2 +}$ so that there are three electrons unpaired making iron as $F e (I)$ and nitrosyl as $N O^{+}$

Magnetic moment of Fe is $3.87 BM$

The colour is due to charge transfer

All of the above are correct statements

Correct answer is (c) The colour is due to charge transfer

Q. [Fe(H2​O)5​NO]2+ is brown-ring complex in NO3−​. In this complex

NO transfers its electron to Fe2+ so that there are three electrons unpaired making iron as Fe(I) and nitrosyl as NO+

Magnetic moment of Fe is 3.87BM

The colour is due to charge transfer

All of the above are correct statements

Correct answer is (c) The colour is due to charge transfer

Q. $[F e (H_{2} O)_{5} NO]^{2 +}$ is brown-ring complex in $N O_{3}^{-}$ . In this complex

$NO$ transfers its electron to $F e^{2 +}$ so that there are three electrons unpaired making iron as $F e (I)$ and nitrosyl as $N O^{+}$

Magnetic moment of Fe is $3.87 BM$