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Tardigrade
Question
Mathematics
f :Q arrow Q is defined by f(x) = 15x + 7 is
Q.
f
:
Q
→
Q
is defined by
f
(
x
)
=
15
x
+
7
is
2659
230
Relations and Functions - Part 2
Report Error
A
injective only
13%
B
surjective only
17%
C
bijective
53%
D
neither injective nor surjective
17%
Solution:
f
(
x
1
)
=
f
(
x
2
)
⇒
x
1
=
x
2
→
f
is one-one
Let
f
(
x
)
=
y
⇒
15
x
+
7
=
y
⇒
x
=
15
y
−
7
∈
Q
∀
y
∈
Q
⇒
f
is onto