Q.
f is defined in [-5, 5] as
f (x) = x if x is rational
= - x if x is irrational. Then
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Continuity and Differentiability
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Solution:
Let a is a rational number other than 0, in [-5, 5], then f(a)=a and x→alimf(x)=−a
[As in the immediate neighbourhood of a rational number, we find irrational numbers] ∴f(x) is not continuous at any rational number If a is irrational number, then f(a)=−a and x→alimf(x)=a ∴f(x) is not continuous at any irrational number clearly x→0limf(x)=f(0)=0 ∴f(x) is continuous at x = 0