Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the statements is incorrect for this reaction?

Question

Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the statements is incorrect for this reaction? (A) Cu2I2 is formed (B) CuI2 is formed (C) Na2S2O3 is oxidised (D) Evolved I2 is reduced

Tardigrade Admin · Accepted Answer

overset-14KI + 2CuSO4 arrow overset0I2 + Cu2I2 + 2K2SO4 overset0I2 + 2Na2 overset+2S2O3 arrow overset+2.5Na2S4O6 + overset-12NaI

Q. Excess of $K I$ reacts with $C u S O_{4}$ solution and then $N a_{2} S_{2} O_{3}$ solution is added to it. Which of the statements is incorrect for this reaction?

$C u_{2} I_{2}$ is formed

$C u I_{2}$ is formed

$N a_{2} S_{2} O_{3}$ is oxidised

Evolved $I_{2}$ is reduced

$4 K I - 1 + 2 C u S O_{4} \to I_{2} 0 + C u_{2} I_{2} + 2 K_{2} S O_{4}$
$I_{2} 0 + 2 N a_{2} S_{2} + 2 O_{3} \to N a_{2} S_{4} O_{6} + 2.5 + 2 N a I - 1$

Q. Excess of KI reacts with CuSO4​ solution and then Na2​S2​O3​ solution is added to it. Which of the statements is incorrect for this reaction?

Cu2​I2​ is formed

CuI2​ is formed

Na2​S2​O3​ is oxidised

Evolved I2​ is reduced