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Chemistry
Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the statements is incorrect for this reaction?
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Q. Excess of $KI$ reacts with $CuSO_4$ solution and then $Na_2S_2O_3$ solution is added to it. Which of the statements is incorrect for this reaction?
The d-and f-Block Elements
A
$Cu_2I_2$ is formed
50%
B
$CuI_2$ is formed
0%
C
$Na_2S_2O_3$ is oxidised
0%
D
Evolved $I_2$ is reduced
50%
Solution:
$\overset{-1}{4KI} + 2CuSO_4 \rightarrow \overset{0}{I_2} + Cu_2I_2 + 2K_2SO_4$
$\overset{0}{I_2} + 2Na_2\overset{+2}{S_2}O_3 \rightarrow \overset{+2.5}{Na_2S_4O_6} + \overset{-1}{2NaI}$