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Question
Mathematics
Evaluate: ∫ limits- 11 log(x + √x2 + 1)dx
Q. Evaluate :
−
1
∫
1
lo
g
(
x
+
x
2
+
1
)
d
x
12
155
NTA Abhyas
NTA Abhyas 2022
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Answer:
0
Solution:
as
lo
g
(
x
+
1
+
x
2
)
is an odd function.
So
−
1
∫
1
lo
g
(
x
+
1
+
x
2
)
d
x
=
0