Ethylene glycol is used as antifreeze to reduce freezing point of water to -2.4° C. What mass of antifreeze is required for 2 L water? (Kf water = 1.86 K kg/mole)

Question

Ethylene glycol is used as antifreeze to reduce freezing point of water to -2.4° C. What mass of antifreeze is required for 2 L water? (Kf water = 1.86 K kg/mole) (A) 16 kg (B) 160 g (C) 1.60 kg (D) 16 g

Tardigrade Admin · Accepted Answer

wsolute=(Δ T f × wwater× Msolute/K f) =(2.4×2×0.062/1.86)=160 g [Mass of 2 L of water is 2 kg.]

Q. Ethylene glycol is used as antifreeze to reduce freezing point of water to $- 2. 4^{\circ} C$ . What mass of antifreeze is required for $2 L$ water? $(K_{f} w a t er = 1.86 K k g / m o l e)$

16 kg

160 g

1.60 kg

16 g

$w_{so l u t e} = \frac{Δ T _{f} \times w _{w a t er} \times M _{so l u t e}}{K _{f}}$
$= \frac{2.4 \times 2 \times 0.062}{1.86} = 160 g$
[Mass of 2 L of water is 2 kg.]

Q. Ethylene glycol is used as antifreeze to reduce freezing point of water to −2.4∘C. What mass of antifreeze is required for 2L water? (Kf​water=1.86Kkg/mole)