Ethanoic acid on heating with ammonia forms compound A which on treatment with bromine and sodium hydroxide gives compound B. Compound B on treatment with NaNO2/dil. HCl gives compound C. The compounds A, B and C respectively are

Question

Ethanoic acid on heating with ammonia forms compound A which on treatment with bromine and sodium hydroxide gives compound B. Compound B on treatment with NaNO2/dil. HCl gives compound C. The compounds A, B and C respectively are (A) ethanamide, methanamine, methanol (B) propanamide, ethanamine, ethanol (C) N-ethylpropanamide, methaneisonitrile, methanamine (D) ethanamine, bromoethane, ethanediazoniumchloride

Tardigrade Admin · Accepted Answer

CH 3 COOH + NH 3 xrightarrowΔ underset text ethanamide CH 3 CONH 2 CH 3 CONH 2+ Br 2+3 NaOH longrightarrow underset textmethyl amine ‘ B’ CH 3 NH 2 + Na 2 CO 3+ NaBr + H 2 O CH3NH2 xrightarrow[(Nano2 / dil HCl)]HNO3 underset textmethanol 'C'CH3OH

Q. Ethanoic acid on heating with ammonia forms compound $A$ which on treatment with bromine and sodium hydroxide gives compound $B$ . Compound $B$ on treatment with $N a N O_{2}$ /dil. $H Cl$ gives compound $C$ . The compounds $A, B$ and $C$ respectively are

ethanamide, methanamine, methanol

propanamide, ethanamine, ethanol

$N$ -ethylpropanamide, methaneisonitrile, methanamine

ethanamine, bromoethane, ethanediazoniumchloride

methanamine, ethanamide, methanol

$C H_{3} COO H + N H_{3} Δ ethanamide C H_{3} CON H_{2}$

$C H_{3} CON H_{2} + B r_{2} + 3 N a O H ⟶ methyl amine ‘ B’ C H_{3} N H_{2} + N a_{2} C O_{3} + N a B r + H_{2} O$

$C H_{3} N H_{2} H N O_{3} (N an o_{2} / d i l H Cl) methanol ’C’ C H_{3} O H$

Q. Ethanoic acid on heating with ammonia forms compound A which on treatment with bromine and sodium hydroxide gives compound B. Compound B on treatment with NaNO2​/dil. HCl gives compound C. The compounds A,B and C respectively are